<p>In the paper 2007, question 3, part (a), I don't understand the solution at all. I'm confused about the areas of polar curves, and prep books aren't helping. (i'm self study...)</p>
<p>also, does anyone know what the curve for calc bc is? what’s the % for a 5?</p>
<p>According to <a href=“Supporting Students from Day One to Exam Day – AP Central | College Board”>Supporting Students from Day One to Exam Day – AP Central | College Board;
<p>AP Calculus BC
Student Grade Distributions
AP Examinations - May 2008
Examination Grade Calculus BC</p>
<p>5 - 30,045 students or 43.5%
4 - 12,008 students or 17.4%
3 - 13,408 students or 19.4%
2 - 4,664 students or 6.7%
1 - 8,978 students or 13.0%
Number of Students: 69,103</p>
<p>You can also find the grade distributions for other subjects by going here: <a href=“College Board - SAT, AP, College Search and Admission Tools”>College Board - SAT, AP, College Search and Admission Tools. Click on the subject and on the left-hand side, click on ‘Grade Distribution’.</p>
<p>^i think he meant the curve…</p>
<p>i think BC curve shouldn’t be too diff from AB’s curve,</p>
<p>probably 60~65+ pts would be the cutoff for 5?</p>
<p>OT
i’d like to know this as well…i suck at polar curves and series~~
where’s themathprof? hehe</p>
<p>I usually dodge the BC questions, as I only teach AB and have long since forgotten half of the BC material. Such as polar curves. :)</p>
<p>That being said, here’s my understanding of it, taking a quickie glance at what’s there:</p>
<p>Let @ = theta. If you wanted to calculate the area of the shaded region, the integral expression represents only the area of the section of the curve from @ = 2pi/3 to @ = 4pi/3. In order to understand what’s going on there, imagine a straight line connecting the origin to each of the intersection points. That divides the region into two sections: (1) a Pac-man like section consisting of the circle (r = 2) from @ = 2pi/3 traced around clockwise to the other intersection point at @ = 4pi/3, and (2) the rest of the shaded region that’s sitting in “Pac-man’s mouth”.</p>
<p>The integral calculates the area of what’s in Pac-man’s mouth. The other piece (the 2/3pi(2)^2) of the area calculation is just finding the fraction of the circle that’s there. In this case, there’s 2/3rds of the circle there (an entire circle encompasses 2pi, and this circle encompasses 4pi/3: 2pi/3 from @ = 0 to @ = 2pi/3, and 2pi/3 from @ = 4pi/3 back to @ = 2pi).</p>
<p>Hope that helps.</p>
<p>^thanks, though i got lost half way lol… kinda sleep right now… i’ll bookmark this and come back later :)</p>
<p>also, this guy has really neat, easily understood notes for calculus…
[Pauls</a> Online Notes : Calculus II - Area with Polar Coordinates](<a href=“Error - Page Missing”>Calculus II - Area with Polar Coordinates)
^there he explains the polar curves etc…
its pretty useful~</p>
<p>I nailed the polar section. yay… </p>
<p>its pretty easy now cuz i know how the limits sweep counterclockwise etc</p>
<p>The curve for BC I believe hovers around 65/108. 75 is a safe 5 (in that it will almost always be a 5 even if barely). Above 90/108 and you’ve pretty much aced the test.</p>
<p>FWIW, I found PR to be very helpful. You’ll get a good feeling for what’s on the test and its explanations are quite good too.</p>
<p>^ty, i have the pr book, and willl start atking them soon :)</p>