<p>What's the antiderivative of 3/(1+x)^2</p>
<p>show steps please :)</p>
<p>To solve it, you will need to use substitution. Let u = 1+x, so du = dx</p>
<p>Substitute u for x so now you have the integral of 3/(u^2) du. The antiderivative of that is -3/u. Resubstituing x+1 for u gives -3/(1+x) as the answer.</p>
<p>-3(x+1)^-1 + C</p>
<p>S = integral sign</p>
<p>u substitution</p>
<p>u = 1+x
du=dx
3du=3dx
3 S u^-2 du
3(-1u^-1)</p>
<p>-3(x+1)^-1</p>
<p>lol u guys got different answers</p>
<p>No they didn't. -3(x+1)^-1 = -3 * 1/(x+1) = -3/(x+1). :)</p>
<p>oh i thought bah's parenthesis were over the whole thing, my error.</p>
<p>thanks guys :)</p>
<p>Ah yes, don't forget the "+C" at the end.</p>
<p>yeah can't forget that horrid +C :P</p>
<p>thanks again for the help :)</p>
<p>Do you really have to make different posts for basically the same type of problem??</p>
<p>yes because other ppl won't read the old post</p>
<p>if you don't have anything nice to say, please don't post at all, you're being rude and should be ashamed of yourself rockermcr.</p>