<p>This is a relatively easy problem, but I have no idea how to solve it. I did some weird thing and got 18/4 ... anyway, the problem:</p>
<p>what is the limit as x approaches infinity : (3x + 2) / the square root of (2x^2 + 3)</p>
<p>and the limit as x approaches negative infinity: same problem...</p>
<p>dunno how to do it but 18/4 isnt the answer. Graphed it on a calc and y reaches somewheres around 2 (2.136 at x = 95) Ill try do to it out after i eat something</p>
<p>3/root(2) is the answer
basicalyl al that matters is 3x and 2x^2.
negative infinity is -3/root2 because it's 3x on the top and it's rootx^2 on the bottom</p>