<p>yagun: i got the same, both open.
setman: max was pi/3 cuz 1 + 2cos(2x) = 0 to max r.
dr/do being negative means that the point is closer to the origin(pole)... so yeah same thing.</p>
<p>The last polar question was tough.. did anyone get it?</p>
<p>Sx91: your right about that man. but V'(20) was not one of those red endpoints. it was V'(16) that was on the red endpoint.</p>
<p>Ok. Regardless, the interval contained those points, right?</p>
<p>anyone else get -5<x<5 for interval of conv. on taylor frq by ratio test?</p>
<p>first polar was...integral from 0 to 2pi of 1/2 (theta + sin(2theta))dtheta for the area right?</p>
<p>I got -1 to 5</p>
<p>for the one about something to 2n, did you get (n-2)(n-1)/ something, clear me up on that</p>
<p>who here didnt skip ANYTHING and got ALL of them</p>
<p>i skipped like 2 letters... the last part of the last question and i think ... i dont remember</p>
<p>coefficient on the taylor with the x = +2 ..?</p>
<p>anyone got 605 for area of one of problems</p>
<p>sx91:</p>
<p>The Mean Value Theorem
If y=f(x) is continuous at every point of the closed interval[a,b] and differentiable at every point of its interior(a,b), then there is at least one number c between a and b at which</p>
<p>f'(c)(b-a) = f(b)-f(a)</p>
<p>so although, the endpoint include the non-differentiable point of (16,20), only the interior of (a,b) determine if the derivative can be taken.</p>
<p>wat were the other FR? we got the area+volume, piecewise velocity, taylor series, polar...</p>
<p>wat were the other two?</p>
<p>there better be a lot of partial credit, I guess I need to go to gradeschool in order to read graphs, feel soooo stupid, anyways how about the the other problems, the noncalc ones before the teaylor?</p>
<p>dru: yes but the slope doesn't change in that interval so you still can't prove that the mean value is in there.</p>
<p>I remember there was a table, and one of the questions were about concavity, or something like that</p>
<p>porcshe: oops my bad :|</p>
<p>o yehh...we had the slope field with the differential equation. one more wat was it?</p>
<p>there was the one with the Euler's method too, and the diff. equation</p>
<p>I made a mistake on the Euler's by the way. It was 1.54 instead 1.86 for what I put, what other parts did the problem have?</p>
<p>find d2y / dx^2 and tell if the euler estimation was over estimated or underestimated. for d2y / dx^2 i got 2 - y'</p>