<p>
[quote]
the interval for taylor is not [-1,5), it is (-1,5). The endpoint -1 will give you (-3)^(2n) which is the same 3^(2n), making the series 1/(2n) which diverges, same with 5, none of the endpts work
[/quote]
</p>
<p>That's what the image in the zip says as well. Sorry if it's not clear, but it mentions -1<x<5 towards the bottom right of the page (and tests of endpoints are in top left).</p>
<p>It can't go past 60. C'mon. '03 was a ridiculously easy test and the curve was, what, 64 for a 5...? Since this was a harder test, I'd imagine the curve would be more lenient? Yeah? Man. This sucks. I'm gonna end up with 4's on all my AP tests, YET AGAIN!</p>
<p>well like pollie says.....usually is in the vicinity of 60-65. and shes right- the BC exam of 2003 required a raw score of about 64 for a 5. that exam was a cakewalk compared to this year's exam.</p>
<p>Gah... I can't believe how many things I screwed up on this test. Going back over it now it really wasn't that hard, or at least not as much as I made it out to be during the test. I just hope I got at least 20 - 25 points in partial credit for the free reponse and that the cutoff for a 5 is somewhere in the low-60's.</p>
<p>If I totally left 2 FRQ's blank and screwed up totally one one of them, what's the best score I can hope for? BTW, I left about 6 blank on the MC.</p>
<p>collegebound123: that really isn't that bad. assuming you got 3 of your FRQ completely right than you got 27 raw pts on that alone. if you only left 6 blank on the MC, that means you did 39 MC questions. using 2003's curve...you would need to have 34 of those correct to get a five on the BC. now, if the curve is less than last's year, you would need even less of your MC correct.</p>
<p>i'd say your pretty safe for a 4....you can definately hope for 5.</p>
<p>I screwed up on the first taylor series part...because i really misinterpreted the sentence about n being odd and derivative being 0...
algebra on interval of convergence was wrong..and I put radius of convergence instead (because that's what I thought I read and for some reason if came out to be a radius)...I remembered absolute value signs! got part b.</p>
<p>q1 is completely right...as it probably is with most...
q3 I got right (I did it right anyway..not totally sure about answers)
parts a,b,c question 5 are right...part d I put no and ********ted an explanation...(from what I've heard they'll give me a point for that).
q4..I messed up some..didn't get part D...and god knows about euler's method...should be ok...but I always make computational errors
q2 got part C..left the rest essentially blank</p>
<p>left 1 multichoice blank on calc section
2 or 3 on noncalc section and I know >for sure< I got at least one wrong...
which means I got more wrong too...let's assume..well..I got 33 right on one of the practice ones (taking into account omits)...so lets assume that...would be a raw of 31...</p>
<p>am I ok? someone tell me I'm not going to die when I see my score...</p>
<p>ahh...long time no see cc...
haven't been here since 2004 :P
i def. screwed up my bc exam...too ashamed to tell my calc teacher that tho -<em>-..i said i did alright..
i think i'll get a 4 max...T</em>T...
i completely got polar wrong...taylor series i had no idea about (the last two chapters on convergence and series, i failed to understand)...therefore, not knowing convergence, improper integrals, and series, half the non-calculator MCs went down the drain.
but
i'm glad it's over..
now only satiis and ap chem and acts...</p>
<p>I have one BIG question concerning the last part of the last question of the free response, the taylor series one . . </p>
<p>To find the interval of convergence, one uses
lim n--> infitniy |an+1/an|, right? But the question says that all even derivatives=0, while odd derivatives follow some formula depending on n, so won't an+1/an equal 0 because every other term in the series is a zero??</p>
<p>Also, one of the polar free response asked for the value of thetha when x-2
I did something with right triangle and got 44 something degrees. Is this right? How do you do it??</p>