<p>It's been bugging me but I forgot how to do it:</p>
<p>F(x) = integral[0, x^2] 1/(2 - t^3) dt
F'(-1) = ? </p>
<p>I think there's something to do with the chain rule? I got 1/3. Is this correct?</p>
<p>I got 1-1/2 = 1/2.</p>
<p>Because isn't the integral basically kind of the derivative. So you would just plug the -1 in for the x, then use the fundamental theorem of calculus?</p>
<p>Okay I'm probably not the best person to ask since I'm really bad at calc.</p>