<p>I know this is not quite the right place, but I was wondering if anybody could help me on this one really hard problem for my calc BC class:</p>
<p>find the lim x--> 0 of (cos(2x))/(3x)</p>
<p>show the work that leads to your conclusion</p>
<p>ty ty ty ty so much</p>
<p>Wolfram is your friend.</p>
<p>[limit</a> of cos(2x)/3x as x approaches 0 - Wolfram|Alpha](<a href=“limit of cos(2x)/3x as x approaches 0]limit - Wolfram|Alpha”>limit of cos(2x)/3x as x approaches 0 - Wolfram|Alpha)</p>
<p>When it comes to limits, you can start to develop intuition by pluggging in a number close to the limit value just to get a feel for what happens to the expression.</p>
<p>In this case, try using x=.01 and then -.01. You’ll see that the cosine term gets close to 1 and the denominator gets close to zero, causing the quotient to blow up to +/- infinity.</p>