<p>For f(x) = 2x^3 - 3x^2 I have to find f'(x) using derivative</p>
<p>I got as my answer:</p>
<p>6x^2 - 6x</p>
<p>Can anyone tell me if this is right or not. Thanks</p>
<p>For f(x) = 2x^3 - 3x^2 I have to find f'(x) using derivative</p>
<p>I got as my answer:</p>
<p>6x^2 - 6x</p>
<p>Can anyone tell me if this is right or not. Thanks</p>
<p>bump-----------------------</p>
<p>correct................................</p>
<p>lol weee thx</p>
<p>isnt this basic differentiation?</p>
<p>well I'm in calc honors, not AP and we haven't gotten up to that yet. Right now we're doing finding f'(x) the long way using derivative so I wanted to make sure my answer was right and that I didn't screw up somewhere in all the messy work.</p>
<p>Use the short way. Multiply the coefficient by the exponent and subtract 1 from the exponent.</p>
<p>wow, you're just getting to derivatives in December? no offense but even our honors did that at least 2 months ago.</p>
<p>I hated doing it the long way, our teacher made us do 20 long problems out, just so we would be able to do it if we were ever asked. I guess its for us, but using 6 pages for 1 hw was a pain.</p>
<p>Yeah, you guys seem pretty far behind...and even if you were only using the definition, you still could have just double-checked...</p>