Calculus Question --- HELP!??

Test Preparation AP Test Preparation
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<p>i dont know if this is in calc AB or BC, cuz im doing calculus I at a community college and i honestly dont know which AP class its equivalent to. however its not too complex. we're using single variable calculus by james stewart, volume 1. section 6.3 #12 (volumes by cylindrical shells).</p>

<p>the question asks for the volume of the solid obtained by rotating the region bounded by the given curves about the X-AXIS.</p>

<p>x = 4y^2 - y^3 , x=0. The section bounds itself in like some sort of semi circle attached to the y axis. The points of attachment are (0,0), and (0,4). 0,4 is found by factoring out a y^2 and getting y^2 (4-y). y=4 and thus, x = 0. Then i rotate this about the x-axis. When doing this, I must find the base (which is simply x or y) and a height. The height is found by taking a random slice at the graph PARALLEL to the axis of rotation. This would make a horizontal slice which has a height in terms of y. My question is, is this correct?</p>

<p>integral from a to b of equation 2pi x f(x) dx (or y works too)</p>

<p>Then i get integral from 0 to 4 of equation 2pi y (4y^2 - y^3). I would just solve that and be correct. The answer i get is 512pi / 5</p>

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<p>I agree with your integral and your answer.</p>

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<p>k thanks. is this AB or BC btw?</p>

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<p>Shell method is actually neither. The College Board took it from the BC curriculum a while ago for some reason. But it's still good to know (just don't use it on the test!).</p>

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<p>there is nothing wrong with using it on the test. The graders won't penalize you for using a method not present in the AP curriculum.</p>

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<p>not even taking the AP test. was just wondering. im trying to decipher whether my class is equivalent to calc AB or all of Calc 1, since nobody seems to know</p>

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<p>uhm pplz, AB + BC = calc 1, correct?</p>

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<p>In most places AB is Calc I and BC is Calc II.</p>

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<p>calc A = intro</p>

<p>Calc B = Calc I</p>

<p>calc C = Calc II </p>

<p>in high school, they combine them for some reason ( AB & BC).</p>