<p>To get to a business meeting, Joanna drove "m" miles in "h" hours, and arrived 1/2 hour early. At what rate should she have driven to arrive exactly on time?</p>
<p>a- m/2h
b- (2m+h)/2h
c- (2m-h)/2h
d- 2m/(2h-1)
e- 2m/(2h+1)
So I plugged in the numbers 60 for miles and 1 for hours and my answer was A. But it's wrong. So please explain (:</p>
<p>I finally figured your username out lol.</p>
<p>Dorky…elmo…
dang… </p>
<p>soory this has nothing to do with ^</p>
<p>Would the answer be E?</p>
<p>I’m thinking (B).</p>
<p>Yep 
How did you answer it…</p>
<p>@hgsoloco : LMAO Congratz!</p>
<p>Distance = m</p>
<p>Time 1 = h
Times 2 = h + 0.5 (you want the trip to take 0.5 hours longer)</p>
<p>Rate 1 = m/h
Rate 2 = m/(h+0.5)</p>
<p>ans:E
v=s/t
v= m/(0.5+h)
v=2m/(2h+1)</p>
<p>@Dorkyelmo;
The common answer anyone would’ve come up with would’ve been “m/0.5+h”, as illustrated above me. However, CollegeBoard must make level 5 questions seemingly insuperable, and therefore you have to look for an equation in the answers that matches your original equation.</p>
<p>2m/2h+1 -> Divide both sides by 2. 2m divided by 2 = m. 2h+1 divided by 2= h+0.5
There you have it. 2m/2h+1 = m/h+0.5</p>
<p>Good luck.</p>
<p>Thank you all!</p>
<p>You can also do this by substituting numbers in like this for example.</p>
<p>Lets say:</p>
<p>Distance = 120 Miles;
Time1 = 2 hours</p>
<p>and Time2 = 2.5; The one we arrive on time.</p>
<p>120/2.5 = 48;</p>
<p>Substitute that for E you will get answer = 48;
2m/(2h+1) = 2(120) /(2*2 + 1) = 240 / 5 = 48;</p>
<p>I hope that made sense :).</p>