Can someone help me on this Math problem please?

Test Preparation SAT Preparation
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<p>A club is buying boxes of candy bars to sell for a fundraiser. If each box contains c candy bars, and each member sells x bars each day, how many boxes are needed to supply enough candy bars for 3c members to sell to sell for 5 days.
A. 15c2x
B. x/15
C. 3x/5
D. 15c2/x
E. 15x
Also, I tend to get these type of problems wrong, does anybody know what they're called, so I can look for extra practice? Thanks!</p>

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<p>If you try googling “a club is buying boxes” you will find many discussions of this problem, including here:</p>

<p><a href=“Math question - SAT Preparation - College Confidential Forums”>http://talk.collegeconfidential.com/sat-preparation/1185394-math-question.html&lt;/a&gt;&lt;/p&gt;

<p>If this type of problem bothers you, you may want to try an SAT classic trick: make up numbers for the variables x and c, get a numeric answer to the question and then put your x and c values into each answer. Rule out any answer that doesn’t match the numeric answer you got.</p>

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<p>If each person sells x bars a day, then over the course of 5 days, with 3c sellers, there will be a total of x<em>5</em>3c=15cx bars sold. But they’re asking for the number of boxes, so we divide by the number of candy bars in a box and get 15x (E).</p>

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<p>Each day, 3c members sell x bars each, so 3cx bars are sold per day. Over the 5 days, 5(3cx)=15cx bars are sold. Since the problem asks for boxes, divide 15cx by c to get just boxes. In 15cx/c, the c’s cancel, and you’re left with 15x. Answer’s E.</p>

<p>It’s an algebraic word problem.</p>

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<p>Food for thought. Since every answer contains an X, what might happen if you rewrite the question by omitting all X? </p>

<p>Like this</p>

<p>A club is buying boxes of candy bars to sell for a fundraiser. If each box contains c candy bars, how many boxes are needed to supply enough candy bars for 3c members to sell to sell for 5 days.
A. 15c2
B. ?/15
C. 3/5
D. 15c2/</p>

<h1> E. 15</h1>

<p>Could the answer be 5*3 c/c or simply 15?</p>

<p>Gotta to love it! </p>

<p>PS You could also give a value of 1 to x with the same result. </p>