Hello,
If someone can help me with these math questions it would be great! Thank you. Here they are:
x^1/3 + y^1/3
I got cube root of x + cube root of y
I wasn’t sure if the x and y both go under one cube root? I hope I am right.
Second question:
b^2-36=ab
a>0 what is the value of a
I wasn’t sure for this question.
Another question:
3x/4y=9/8 what is the value of x/y
I got 3/2. I hope this is right as well.
Thank you again
@cusnew I’m not sure what the question is here.
You can solve for a in terms of b by dividing by b (assuming b is not zero) - you get a = (b^2 - 36)/b. But I am not sure if this is the question you asked. Please post the full questions.
Yes, x/y = 3/2. You can visualize it as (3/4)*(x/y) = 9/8, then multiply both sides by 4/3 to get the value of x/y.
Hey, thank you for the quick response @MITer94 The first question was a multiple choice question, it showed this x^1/3 + y^1/3 then had choices of cube root of x plus cube root of y, this is what i circled and I am hoping it is right? The other choice I was stuck on was cube root of and y under on radical I think. I would like to know if I am right or wrong here. Second one: the b^2 was a grid in and asked for the value of a. I wasn’t sure for this one, unfortunately.
Nevermind, I’m good with cube root one. Thank you for the help!
Sorry, what is the value of a? That one was tough for me 
Anyone know?
Where is this problem from?
Did the problem happen to specify that a and b are integers?
If so, it’s about factoring.
Write: b^2 - ab -36 = 0 and then look for possible ways to factor it…
@cusnew so far you haven’t provided enough information to solve the b^2 - 36 = ab.
As pckeller noted, if a > 0 and a and b are constrained to be integers, then you could find a set of possible values for a – one way you could do this is rewrite a = (b^2 - 36)/b as a = b - (36/b). So b is necessarily a factor of 36. If b = 9, for example, then a = 9 - 36/9 = 5.
Oh, okay! Thank you for the help guys!