<p>Maria has 74 pebbles that she wants to divide into 25 piles. If the tenth pile is to have more pebbles than any other pile, what is the least number of pebbles Maria can put into the tenth pile?</p>
<p>I think the answer is 4. The other 24 piles can have 2 or 3 pebbles to use the remaining 70. The answer is not 3, since if all 24 other piles had 2, not all pebbles would be used.</p>
<p>Just confirming, it is 4.</p>
<p>74/25 = 2.96</p>
<p>That means all the piles will either be 2 or 3 pebbles.
If all the other piles are 2 or 3 that means the 25th needs to be 4.
74 - 4 = 70/24 = 2.92 </p>
<p>2 * 24 = 48
Thus, 3 being the size of the 25th pile is impossible.
2.92 * 24 = 70
Thus, 4 is the size of the 25th pile.</p>
<p>Ok, so basically 2.96 = 3 pebble per pile but since the tenth pile has to be greater than any other pile, then it has to be greater than 3. </p>
<p>So 4 is the best answer because 3<em>24= 72 and 72+4= 76 which is greater than or equal to 74. (3 doesn’t work because 2</em>24=48 ----------> 48+3= 51 so its way off)</p>
<p>Is this analysis correct lol?</p>