Can you help me on these kinematic physics problems?

<p>Here are the equations used in this:
Vf = V0 + at
x=x0+v0t+1/2at^(2)
Vf 2 = V02+2a(xf-x0)</p>

<p>where vf equals final velocity
v0 stands for initial velocity
xf=final
x0 stands for initial</p>

<ol>
<li>Using equation (1) solve for t given that v0=5 m/s, vf=25 m/s, and a=10 m/s^2</li>
<li>Given v0= 0 m/s, x0=0 m and t= 10 s, use the second and the third equation together to find xf.
3.a=10 m/s^2, x0=0m, xf=120m, and v0= 20m/s. Use the second equation to find t.</li>
<li>vf=-vo and a= 2m/s^2. Use the first equation to find t/2.</li>
<li>How does each equation simplify when a=0 m/s^2 and x0= 0m?</li>
</ol>

<ol>
<li>25=5+10a=>a=2</li>
<li>I’m not sure if you can solve that…you’re given an object starts at rest and travels for 10 seconds, and you have to find the distance it travels without velocity or acceleration?</li>
<li>120=20t+5t^2, solve the quadratic</li>
<li>-v0=v0+2t=>t=-v0=>t/s=-vo/2</li>
<li>vf=v0, x=v0t, vf^2=v0^2</li>
</ol>

<p>Was this on your ap physics summer assignment? I’m doing mine right now and I’m stuck. Do you still have the packet? Lol I know it’s been 2 years</p>