<p>1.) x+1/x-3 - 2x-4/ x( SQUARED) minus 9) = 1
solve for x</p>
<p>2.) x/x-3+x-2/2=5x-3/4x-12 solve for x</p>
<p>3.) x+1/2x+6 - x-2/2x-6= 9/x ( SQUARED) minus 9)
solve for x</p>
<p>1.) x+1/x-3 - 2x-4/ x( SQUARED) minus 9) = 1
solve for x</p>
<p>2.) x/x-3+x-2/2=5x-3/4x-12 solve for x</p>
<p>3.) x+1/2x+6 - x-2/2x-6= 9/x ( SQUARED) minus 9)
solve for x</p>
<p>you need to learn how to use parentheses</p>
<p>does this have anything to do with the SAT?</p>
<p>i’ll help you with one…</p>
<p>your common denominator is (x^2-9) … multiply the first fraction by ((x+3)/(x+3)) … you should get, after adding, (x^2+2x+7)/(x^2-9) = 1 … x^2+2x+7 = x^2-9 … 2x+7 = -9 … x=-8</p>
<p>then again, graphing calculators are magical.</p>