Can you solve this Algebra Equation Problem?

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1

<p>c = 2cd/a-d</p>

<p>Also could you explain the answer? I've read through the chapter where it explains these things but there just wasn't enough examples for me to get it.</p>

<p>Thanks again</p>

2

<p>Sorry, solve for d</p>

3

<p>Ok.</p>

<p>c=2cd/a-d
multiply both sides by a
ac=2cd-ad.
factor d out on right side
ac=d(2c-a)
dividie both sides by 2c-a
d=(ac)/(2c-a)</p>

4

<p>Thats not the answer the book has… It says its supposed to be d = a/3
I just dont know how they got that? Can anyone cur with the book or the previous poster as to what the correct answer should be?</p>

5

<p>If you meant c = 2cd/(a-d)…in that case it will be the same idea of moving terms (you have to cancel out the c’s). You should try this one too.</p>

6

<p>Yea you mistyped the problem. I have the right answer for the problem you typed.</p>

<p>You meant c=2cd/(a-d), which actually is a lot nicer.</p>

<p>Cancel out the c’s.
1=2d/(a-d).
Multiply a-d to both sides
a-d=2d.
Move -d to the other side
a=3d =>
d=a/3.</p>

7

<p>Also I don’t understand how you were able to get rid of the divided by sign in step two. Shouldn’t that step have yielded ac=2cd/-d ? How are you able to factor out the d if its d/d?</p>

8

<p>huh? You mistyped your problem. I did the problem</p>

<p>c=2cd/a-(d). Where that d is not part of the long division in the demoninator.</p>

<p>So you multiply both sides by a in that problem to get ca=2cd-ad. Then you can factor out the d for that problem to get ca=d(2c-a).</p>

<p>That was not your problem…since you said the answer was d=a/3, your problem was actually c=2cd/(a-d), which is a huge difference. Look at my second post as I did that problem too. </p>

<p>Basically, you asked what is 4/2-1, when you meant what is 4/(2-1).</p>

9

<p>Hey thanks. The confusion lied in I didn’t express the problem correctly as you pointed out. My book only has 3 practice problems and I need some worked out problems so I can practice and see how a problem is solved should I be unable to.</p>

<p>Thanks again</p>

10

<p>Hey if you want to check your work, you can also plug in numerical values for a and c, and then get a value for d. Then plug in a,c,d back into the equation and see if the equation is satisfied.</p>

11

<p>I know, I knew my answer was wrong, I just didn’t know how to get it right.</p>