<ol>
<li>Semicircular arcs AB,AC,BD,CD divide the circle above into regions. The points show along the diameter AD divide it into 6 equal parts. If AD=6, what is the total area of the shaded regions?
a.4pi
b.5pi
c.6pi
d.12pi
e.24pi</li>
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<p>How do i do this problem? I've looked on Google, but I haven't found a good through explanation. So, can someone please give me a very good explanation as to how you got the right answer?</p>
<p>This is a question from the Blue Book. Test 3, Section 2, Question 17 on page 518.</p>
<p>Here’s two ways to solve it:
AD = 6 = diameter. Therefore the radius is 3. Therefore area of the whole circle is 9pi. Cross out answer choices D and E.</p>
<ol>
<li><p>Eyeballing the top 1/2 of the circle. The unshaded region is less than 1/2 of the shaded region. Therefore the answer is greater than 1/2 the area - 4.5 pi. Throw out answer choice A. </p></li>
<li><p>The unshaded region is definitely closer to 1/4 than 1/2 of the shaded region, so the answer should be closer to 6pi than 5pi. Therefore choose choice C.</p></li>
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<p>Here’s the mathy way to solve it:
Area of whole circle is 9pi</p>
<p>2.Just look at the top 1/2 of the circle. The shaded area is arc AD - arc AC then we need to add back in arc AB. </p>
<ol>
<li><p>Area of arc AD is 4.5pi (just 1/2 of the whole circle) Area of of arc AC - diameter is 4, therefore radius is 2, therefore area is 1/2 pi 2^2, which is 2pi. Area of arc AB - diameter is 2, therefore radius is 1, therefore area is 1/2 pi1^2 which is 1/2 pi.</p></li>
<li><p>So 4.5 pi - 2 pi + .5 pi = 3 pi. But this is just for the top 1/2 of the circle. So multiply it by 2 to get the shaded area of the whole circle 3 pi x 2 = 6pi. Answer C.</p></li>
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