CHALLENGE MATH...or not?

<p>This is from CB.</p>

<ol>
<li>If x and y are integers, 7 < y < 16, and x/y = 2/5</li>
</ol>

<p>how many possible values are there for x ?</p>

<p>A) One
(B) Two
(C) Three
(D) Four
(E) Five</p>

<p>Its actually a level 3 out of 5, the only one I missed out one section.</p>

<p>Answer with explanation would be nice.</p>

<p>Thank you. :)</p>

<p>the (x/y = 2/5) is similar to saying …x over y is equal to 2 over 5 …</p>

<p>I couldn’t copy that exact symbol onto this format thanks.</p>

<p>Well since x and y are integers and since x/y = 2/5
then x = 2y/5</p>

<p>Since x is an integers y must be divisible by 5 or a multiple of 5.
Between 7 and 16 there are only 2 multiples of 5 making two distinct answers for x.
The Answer: B</p>

<p>Is the answer B?</p>

<p>i was stuck between two or three, cuz…should you count 2 as a value of x? if not then its B. Two. However, if 2 can be a value of x, then three…</p>

<p>my fault^ its two for sure, sorry i feel real lightheaded right now, i missed the y has to be bigger than 7.</p>

<ol>
<li>If x and y are integers, 7 < y < 16, and x/y = 2/5</li>
</ol>

<p>how many possible values are there for x ?</p>

<p>A) One
(B) Two
(C) Three
(D) Four
(E) Five</p>

<p>One of the values is 4. –> x/y = 2/5 –> 2x/2y = 4/10
Y= 10 in this ratio and 10 > 7, x must be 4.
The other is as followed –> x/y = 2/5 –> 3x/3y = 6/15 –> x =6 so the answer is B. 2</p>

<p>there is no limitation for x !!</p>

<p>^Yes there is. </p>

<p>x is limited to y such that x/y = 2/5.
Also x and y have to be integers, so you can’t go into decimals.
Because the is a limit to y (7 < y < 16), there is also a limit to x.
Only 2 way to satisfy the equation (x=4;y=10 and x=6;y=15), the answer is B.</p>