If 0.050 mol of the hydrate Na2SO4 * x H2O loses 9.0g of water when it is completely dehydrated, the value of x in the formula for the hydrate is
the answer is 10.
What I tried was to change 9 grams of water into moles. 9 * 1/(2+16) = 0. 5 mol .
Since 9g of water is equal to 0.5 mol, H2O in reactant should equal to 0.5 mol. so 0.05 * 10 is equal to 0.5.
I am not even sure if these steps are correct. anyone?