College Board Actual Question Math Help!!!

<p>Can someone show me step by step how to do this?</p>

<p><a href="http://img134.imageshack.us/img134/9608/sathelp.png%5B/url%5D"&gt;http://img134.imageshack.us/img134/9608/sathelp.png&lt;/a&gt;&lt;/p>

<p>x^2= 4(y^2)
if x= 2y+1
replacement:</p>

<p>(2y+1)^2= 4y^2
(2y+1)(2y+1)
4y^2 + 4y+ 1 = 4y^2
4y+1= 0
4y= -1
y= -1/4</p>

<p>x= 2y+1
x= 1/2</p>

<p>Wow thanks. I realized my dumb mistake at “4y+1= 0”. I didn’t bring 1 to the other side and was stuck.</p>