<p>can anyone explain how to do #16 on pg 859? thanks</p>
<p>747 / 16 / <a href="http://talk.collegeconfidential.com/showthread.php?t=103086%5B/url%5D">http://talk.collegeconfidential.com/showthread.php?t=103086</a>
859 / 16 / <a href="http://talk.collegeconfidential.com/showthread.php?t=103073%5B/url%5D">http://talk.collegeconfidential.com/showthread.php?t=103073</a></p>
<p>Correction:
in the previous post 807 / 16 / should be
747 / 16 / <a href="http://talk.collegeconfidential.com/showthread.php?t=103086%5B/url%5D">http://talk.collegeconfidential.com/showthread.php?t=103086</a></p>
<p>599 / 17 / <a href="http://talk.collegeconfidential.com/showthread.php?t=110743%5B/url%5D">http://talk.collegeconfidential.com/showthread.php?t=110743</a></p>
<p>Soemone has to have the studyworks answers saved as a PDF file and hosted somewhere...</p>
<p>Is pg. 427 #15 and pg. 426 #11 somewhere? If not, can u explain?</p>
<p>wait studyworks doesn't have answers for the blue book..it only has them for the other books = (</p>
<p>page 427, #15.</p>
<p>We know that x = -3 at point P and x = 3 at Q (b/c PQ = 6, and can be divided into 3 on each side b/c parabolas are symmetric, and y = x^2 specifically is symmetric about the y-axis). </p>
<p>Plug in to y = x^2 to find the y value. y = 3^2 = 9.</p>
<p>Now plug into the other equation, with y = 9 and x = 3...</p>
<p>9 = a - (3)^2
9 = a - 9
18 = a</p>
<p>ok this is completly stupid but i can never get these dumb blue book problems...ok so can ne one help me with it?
In a rectangular room 30'x12'x12', a spider is at the middle of an end wal, on foot from the celling
The fly is at the middle of the opposite end wall, one foot above the floor. The fly is so frightened it cant move.
What is the shortest distance the spider must crawl in order to capture the fly?(hint less then 42') i may seem totally stupid but i need help and my teacher wont help ne one out with these so i hope u help...thanks</p>
<p>Look at a cross-section of the room, which gives you a rectangle. Try dividing the rectangle into smaller rectangles and a triangle. You'll end up with a triangle with legs 10' and 30' feet long. Then you can use the Pythagorean Theorem to find the diagonal length. :) </p>
<p>Answer ~31.5'</p>
<p>Wouldn't that only work if they spider could fly across the room? The problem talks about the spider crawling, which made me think that it was restricted to staying on the walls of the room...</p>
<p>Nonsense. It can crawl across on a web...they didn't say it had to crawl acoss the wall. :p </p>
<p>However, if you insist that the spider cannot do that, then I advise macy to think of the room as an unfolded box, which is probably the easiest way to solve it.</p>
<p>Would not it make sense to keep this thread for what it was originally intended - a list of references to the Blue Book math solutions in this forum, and post questions separately?</p>
<p>Could someone plz help me out on problem #18 on page 599 of the blue book.</p>
<h1>18, p. 599</h1>
<p>Based on information supplied to us from the diagram, we know that BC = 1 and AD = 1. To give ABCD an area of 4, DC and AB must have lengths of 4. Since the x-axis bisects the two vertical sides of the rectangle, the segments between the x-axis and the points must have lengths of 2 each. Ergo, a = -2, b = 2, c = 2 and d = -2. </p>
<p>Let's use point C b/c the numbers are all positive...
y = px^3
2 = p(1/2)^3
2/(1/8) = p
2*8 = p
16 = p</p>
<p>hah i just realized how simple it is. thnx a lot</p>
<p>Hi. Can anyone help me on p. 488 # 4? I know it's a really easy problem, but somehow I'm not getting the exact answer they're getting. Thanks.</p>
<p>p. 488, #4</p>
<p>You'll be using a box of 12, a box of 6, and 3 individually-priced donuts to get the lowest possible cost of 21 donuts. So...3.59 + 1.89 + 3(0.40) = 6.68, (B)</p>
<p>mayyn didn't think it that way, thanx</p>
<p>I have another question, anyone? number 598 #13, somehow, i'm missing something..</p>