Couple of SAT I Math Questions

<p>These are from the CB online practice test 3</p>

<p>The first one gives a chart of instructions…which goes as follows:</p>

<p>Step 1: Choose a number n greater than 2.</p>

<p>Step 2: In n is prime, add 5. If n is not prime, add 2.</p>

<p>Step 3: Divide the result of step 2 by 2.</p>

<p>Step 4: Find the greatest integer less than or equal to the result of step 3.</p>

<li><p>In the chart above, if the number n chosen in step 1 is 39, what number will be the result of step 4?
(I found the answer to be 23…but apparently its 20)</p></li>
<li><p>HOw many positive integers less than 1,000 are multiples of 5 and are equal to 3 times an even integer?
(I got 30…but its supposed to be 33)</p></li>
</ol>

<p>Any help is appreciated!</p>

<p>15) Start w/ 39. It's not prime so add 2 = 41. Divide by 2 = 20.5 Greatest integer LESS THAN OR EQUAL TO 20.5 = 20</p>

<p>18) This is pretty much asking what numbers 1-999 are multiples of 5 AND multiples of 6 (3 x even integer = 6x). By cross multiplying the question now asks what numbers 1-999 are multiples of 30. So our numbers are 30...30+30...60+30.............960+30. You can add them all up to get 33 OR the easier way would be to take the highest multiple of 30 that is value 999 or less. This is 990. Then dividie that by the multiple (30). 990 / 30 = 33.</p>

<p>ohhh okay i see where my mistakes are now. thanks</p>