<p>I think it was W too. Anyone else ? If T > W then the two block must have accelerated upward (which of course, doesn't make sense).</p>
<p><a href="http://i35.tinypic.com/5fol8w.jpg%5B/url%5D">http://i35.tinypic.com/5fol8w.jpg</a></p>
<p>OH WOW...I feel so stupid now. I totally did not read the pulley question thoroughly enough. Messing around with the other string got me utterly confused and motivated me to put down 0. T_T</p>
<p>^ Wow Modernchem that is an extremely convincing proof.</p>
<p>and wasnt this the relativity one?
<a href="http://i34.tinypic.com/i2iud2.jpg%5B/url%5D">http://i34.tinypic.com/i2iud2.jpg</a>
making the particle move at 1.2c RELATIVE to the plane, or did I miss something?</p>
<p>im still not convinced about the pulley question, the SAT puts tricky questions that mainly meausre comprhension not keen observation (which is very important in fact). a classic trick question is "feathers and hammers" according to princeton review - two masses are dropped from the same height M1 = (2)M2. which falls faster? of course same speed and time. but i dont think that pulley question was that different. all the pulley questions are treated the same. so i really hope that this one was too. otherwise, well, did i mention how much i hate collegeboard and ETS?!</p>
<p>what did u guys think of the test?
was it hard, mediocre, or easy?</p>
<p>modernchem</p>
<p>look @ sparknotes on pulleys. tensions is T for both sides and tension is the same in all parts of string. pretty sure its W. also while 1.2c seems to make sense, at relativistic speeds nothing can go faster than c even if in regular speeds it would go at 1.2c.</p>
<p>what was ans to galvinator q?</p>
<p>also toward the beginning was Frequency the ans twice? and which were the waves out of phase?</p>
<p>For the pulley question, find the tension of each side first. Since both weights are equal, tht tension of each side is the same. In addition, tension is equal throughout the pulley. </p>
<p>Net force=ma
T-W=ma
T=W</p>
<p>rb3, it was asking for the tension in the rope that the pulley is hanging from, not the tension in the rope on the pulley. <a href="http://i33.tinypic.com/epexhc.jpg%5B/url%5D">http://i33.tinypic.com/epexhc.jpg</a></p>
<p>The hanging rope is not part of the pulley</p>
<p>and yea I got frequency twice. the waves that were out of phase were the ones that had the same wavelength and amplitude but one was slightly shifted</p>
<p>ModernChem is right, it was asking for the tension of the rope holding up the pulley/mass system</p>
<p>Thus, the answer is simply 2W</p>
<p>Wow, I'm so cut. I thought they were asking for the tension on the pulley rope. Ugh....</p>
<p>I thought they were asking the tension of the pulley in the rope too. might have read it wrong? i didnt even see another rope on top.</p>
<p>tension is equal to W, not 2W.</p>
<p>and i put the heat dissipated as 2h. P=(i^2)R, so power is directly proportional to resistance. at a constant current, the more resistance, the more kilowatt hours (and heat).</p>
<p>for the heat one did it say the heat dissipated in twice the time? b/c the 20 ohm resistor had half the resistance but double the time.. i think.. so that wouldnt it be h?..</p>
<p>Wait, did it say half the time. Wow, I can't read... I just look at the diagram and read the question and answers.</p>
<p><a href="http://i37.tinypic.com/30k4n5l.jpg%5B/url%5D">http://i37.tinypic.com/30k4n5l.jpg</a></p>
<p>rb3: Half the time? Weren't the resistors in the same circuit? The time would have to be the same... H=(I^2)Rt, so the 2R resistor gets 2H...</p>
<p>Same time and they were asking for the heat dissipated by the 20-Ohm resistor if I am not mistaken. Thus, it was 1/2H.</p>