December 2010 - SAT Math 2 Thread

<p>If I remember correctly, here is the surface area problem:</p>

<p><a href=“http://img443.imageshack.us/img443/2779/surfacearea.png[/url]”>http://img443.imageshack.us/img443/2779/surfacearea.png&lt;/a&gt;&lt;/p&gt;

<p>@nhart, if the problem had the variable x as the argument of the trigonometric function, it is stating that ALL values of x in that equation will be equal to whatever they stated.</p>

<p>Okay, I don’t know. I could very well be wrong on the sin+cos question. That’s just what I remember thinking when doing that problem.</p>

<p>OMGG!! I took it and I ran out of time…I couldn’t do 8 problems & I put C’s for all 8 problems…If there were at least 2 C’s it makes up for 4 wrong? Anyways I really don’t lknow why I guessed. WERE THERE AT LEAST 3 C’s for problems 42~50?
:0</p>

<p>not sure what the problem was asking for exactly either</p>

<p>was the problem with sinx and cosx None or II and III?</p>

<p>For sinx, cos x. It was not “none”</p>

<p>sin^2(x)+2cos^2(x)=2 when x=0
2sin^2 (x)+cos^2(x)=2 when x=pi/2
That’s what I got</p>

<p>^ I’m 100% sure it was II and III</p>

<p>What did u guys get for the question where it stated if 3 and 2+i were roots, which of the following could also be the roots of the question?
The answers had like
-3,
2-i
-2-i</p>

<p>and I cant remember the rest.
Good luck to everyone on this thread!!</p>

<p>Question #46 </p>

<p>what is x^30y equal to when x^5y=2a</p>

<p>was choice C, I think 6a^6 i dont remember exactly the answer but it was Choice C.</p>

<p>Yeah…I remember 6a^6 too.^^</p>

<p>pink11, I put 2-i</p>

<p>and xxjinax, yeah, pretty sure 50th was C.
log(1-sinx)+log(1+sinx)=log(1-sinx^2)=logcosx^2=2logcosx</p>

<p>“for the ax^2 + Bx + c one, doesn’t B have to be non zero? I think it said two distinct real roots, which means b^2-4ac must be greater than zero. or am I forgetting the exact question?”</p>

<p>If the A could be 0 it would be a line. Which can only have 1 root. 2x^2+0x+2. That has multiple real roots.</p>

<p>With the discriminant approach, it just means either a or c must be negative.</p>

<p>It said what should <em>not</em> be zero for the function to have 2 zeros, so A^^</p>

<p>Did anyone get this as an answer</p>

<p>abs(x) greather than something, and except x not 0 Not sure if the answer choice had except 0 or 2)??</p>

<p>^ the answer was a having to be non-zero because that was the only squared term. Yeah I wasn’t thinking when I did the problem thinking b^2 -4ac had to be positive, therefore b could not be non-zero. So far thats the only one that I know I got wrong though lol, so theres still a slim chance of an 800. :)</p>

<p>yeah there was something abs(x) >= 2, and not zero or something like that. I have no idea what the problem was though.</p>

<p>Goodluck^
I always <em>always</em> make really stupid mistakes, so I double-checked everything. As a result, I had to leave at least 8 blank…don’t remember exactly how many. ;<</p>

<p>shahdin: I remember something about x=/=0 and x being same as or above (or below?) |2|, I think…</p>

<p>Did anyone get this as an answer</p>

<p>abs(x) greather than something, and except x not 0 Not sure if the answer choice had except 0 or 2)??</p>

<p>is everyone positive about the sin(theta)cos(theta) roman numeral question being II and III as the answer?</p>

<p>YES.</p>

<p>and it was 156ish</p>

<p>What about the 3 and 2+ i one? I put -3 and 2 - i</p>

<p>put just 2-i</p>

<p>and about sins, I remember there there being at least 2 correct answers (the one where sinx=1 and cos is disregarded and the other way around)</p>

<p>@Marie: I think the answer was lxl greater than of equal to 2 (Not sure what equality sign) and x not equal to 0. ( I also kind of remember that the answer choice was C.)?</p>