December 2010 - SAT Math 2 Thread

<p>It was the perfect square one… factoring gave m^90(m + 2) and m = 34 gave two perfect squares so I’m also positive it was right…</p>

<p>@undefeatedat what was the exact problem statement?</p>

<p>anyone did the ball bouncing height question? What was the answer for it?
i got 5…wasn’t sure how to do it…guessed</p>

<p>@undefeatedat - If we’re thinking the same thing - the question said two real solutions, so it had to have at least 2nd degree. I chose A mustn’t be 0.</p>

<p>@undefeat yes that’s right… @ supernova no the limit was 2</p>

<p>I think it is what has to be nonzero in order for Ax^2+Bx+C=Dx+E to have 2 real solutions.</p>

<p>I don’t feel comfortable posting the exact problems… the answer for the ball one was 3…</p>

<p>ans for the ball question was 3 times</p>

<p>@spratleyj: so the equation stated that lim x -> 2? Then how are people getting 2 for their answers? I was trying to confirm if the problem statement said lim x -> 1 (once again, I didn’t take the test so someone needs to confirm).</p>

<p>@undefeatedat: Yes. 0 should be the answer. You cannot have 2 real solutions for the equation if x is only to the first degree.</p>

<p>=( 10characters</p>

<p>@ Supernova no the answer was 2</p>

<p>x was definitely x->1. I remember that vividly.</p>

<p>the limit question was as x approaches 1, so ans = 2</p>

<p>@truzzi182: Which one MUST be 0 for 2 real solutions? B, C, D, and E works out then because x^2 is still there.</p>

<p>@spratleyj: That’s what I said in the first place… the equation says lim -> 1, which means 1+1 = 2 >_></p>

<p>If you need any more help, feel free to ask away. Sounds like this test was slightly challenging, but not that hard.</p>

<p>@truzzi No that was not the question, because there wouldn’t be an answer if it was!</p>

<p>@supernova oh sorry must have misread…</p>

<p>The ball’s isn’t 4?</p>

<p>10 feet= 120 inches</p>

<p>120 x 0.4 x 0.4 x 0.4 = 7.68…
120 x 0.4 x 0.4 x 0.4 x 0.4 = 3.072</p>

<p>I put a for the ax^2 +bx + C= -dx + e one because you need the second degree to have two solutions.</p>

<p>For the bouncing ball, it started at 10 feet=120 inches. You just need to put Ans*.4 into your calculator. I got 4.</p>

<p>120 initially - bounce - 48 - bounce - 19.2 - bounce - 7.68 - bounce - 3.072. You need 4 bounces before it rebounds to a height less than 6 inches.</p>

<p>For the exponent one I just crunched it into my TI-Nspire and choice E was the only integer.</p>

<p>I got 2 for the limit question.</p>

<p>@spratleyj: No problem ^^*. At least you’re one step closer to 800!</p>

<p>Yup, I’m *<strong><em>ed. I originally had the right answer and changed it. LOVELY. If I get a 780/790 I will literally *</em></strong> a brick, i ALWAYS do this.</p>