<p>ABOUT THE BALL PROBLEM</p>
<p>THE ANSWER IS 4</p>
<p>because it was asking how many times it bounced at least to become less than 6inch</p>
<p>u start out with 10 feet = 120 inches
after a bounce its 0.4 x 120</p>
<p>after 2 bounce 0.4 ^ 2 x 120</p>
<p>3 bounce 0.4 ^ 3 x 120</p>
<p>after 4 bounce it is finally less than 6inch</p>
<p>I THOUGHT THE TEST WAS NOT HARD AT ALL</p>
<p>do you remember the matrix question? determinant? was it 4(C)? not very sure…I think I put a + instead of a -, and I`m afraid I put a wrong answer 
what about f(x)…continuous function for all real numbers…or discontinuous for x=2?</p>
<p>@luckyjinwon: That’s what I’m thinking, but we all have different skills. I suck at English since it’s my second language, but I’m pretty good at math since it’s a universal language XD</p>
<p>@ritaalbu: do you remember the exact problem statement?</p>
<p>The matrix determinate one was 0. My calculator said so.</p>
<p>Oh I thought for the ball that it wasn’t counting the first bounce?</p>
<p>YEP THE MATRIX WAS 0 </p>
<p>if you use the coefficient in determinant it says 0</p>
<p>f(x)= x(x-2)(x-4) / (x-2)…smth like that…continuous for all real no., or discontinuous x=2? i thought that (x-2) simplifies</p>
<p>^ discontinuous at x = 2</p>
<p>@ritaalbu: Continuous for all real no. Simplification does the trick.</p>
<p>If you don’t believe me or have doubts, draw it out on a TI and see if there’s v.a.</p>
<p>EDIT: @spratleyj: <a href=“(x(x-2)(x-4) - Wolfram|Alpha)+/+(x-2%5B/url%5D)”>(x(x-2)(x-4) - Wolfram|Alpha)+/+(x-2)</a></p>
<p>i said at x=2 only is discontinous.</p>
<p>because x-2 is where theres a whole, so the whole must be at x-2=0, so x=2…not sure, anyone agree?</p>
<p>the distance in the (a,b) (c,d) (e,f) was like 5 right.a,b,c,d,e,f had values btw i just dont remember them</p>
<p>and also for the (a,b) was it (-a, b)???</p>
<p>BALL PROBLEM IS 4…
why would it be 3?
after first bounce it is 0.4 x 120
after second 0.4 0.4 120
third bounce 0.4 0.4 0.4 120 which is still bigger than 6…</p>
<p>and the vector problem…</p>
<p>didnt a vector coordinate be = (+,+)?
b vector also was (+,+)?</p>
<p>if you add b-a > it is same as b+ (-a)
which means that it will point to third quadrant </p>
<p>not fourth quadrant…
because a will be -,- and b will be +,+…</p>
<p>The ans for the discontinuous problem is 2.</p>
<p>Anyone remembers which graph was symmetrical about the origin?</p>
<p>Its definitely discontinuous at x = 2, because its undefined!</p>
<p>I hope the curve’s lenient…</p>
<p>What’s would 9-10 omits probably result in?</p>
<p>@spratleyj: Let me make sure first: was the equation (x(x-2)(x-4)) / (x-2)?</p>
<p>And the vector was definitely quadrant 2, you just had to look at the components. A<em>y > B</em>y and B<em>x > A</em>x</p>
<p>@ lucky, hah i dont know man. i guessed B cause i figured i had to be positive and j be engative.</p>
<p>I agree. The only discontinuity is at x=2.</p>
<p>For the problem with the trough and the volume, the correct answer was 18sin(theta) ft^3. I got it but now I’m getting paranoid and I think I bubbled it in wrong. Does anyone remember which answer choice that was?</p>
<p>yes, that was the function.</p>