<p>hikin knows what up, whatd u get for the box plot one @hiking</p>
<p>@ders12: Yeah, two left of (2,4) is (0,4)</p>
<p>@ders12: you mean the one probability one which was a circle inside a square? Yes, it’s pi/4</p>
<p>The question where it showed the graph of f(x) and g(x)…
And it said when is f(x) - g(x) = 0</p>
<p>was x =2? or -2?</p>
<p>I think it was question #22 or something on the exam</p>
<p>does anyone remember if that was C or D equalling pi/4</p>
<p>@jimjones:
Boxplot: I only (more than 50% of A > 50% of B)</p>
<p>@flayev: x=2 for f-g=0</p>
<p>I think -2 @flayev. it was a negative number</p>
<p>@hiking7610, the range of box plot a was 5 to 10 and the range of box plot B was 1 to 8 so III would be correct also, making the answer E</p>
<p>also what question does x=2 for f-g=0</p>
<p>dam pls tell me hiking is wrong on both answers he just gave. the two graphs crossed at a negative x, hence, =0. With the box plot, i thought the third one was right, i dont remember what it said tho</p>
<p>So far I got one wrong and omitted one. This means that I can get a maximum of 4 more wrong and still get an 800. Right?</p>
<p>what did it look like haha i don’t remember the second part of the crossing, was it the two parabolaS?</p>
<p>I got I and III for the box plot. For the one where a=2, does anyone know the whole question? </p>
<p>It was (x+2)^2 = …</p>
<p>what about the linear regression one?</p>
<p>Yes III said that the range of the top one was greater than the range of the bottom or something like that, which is true, so I and III are both true.</p>
<p>And for the f-g one, wherever the graphs crossed is the right answer. I don’t remember if it was -2 or 2.</p>
<p>Anyone remember the problem somewhere in the 50s. It said h(x)=sinx. g(x)=cosx
g(f(x))=h(x)</p>
<p>no we dont rishab chawla, but the answer was a=2 for sure. I will give u my heart if it isnt
and
@ders12 the two crossed on the left of the graph. I forgot if they were parabolas or not, but it was really easy to solve that at x=-2,3 the both values was like 2. so 2-2=0</p>
<p>@greenleaf4, it was definitely -2 for sure. I remember the graph.
@ders12 I think i got a middle answer for that. so like c,d</p>
<p>x^2 + 2x + 4 = (x^2 + 4x + 4) + (ax+2a) + b. for any value x i think it said</p>
<p>what was the answer for the equilateral triangle (1, -√3)?</p>