<p>x = .3 (box-figure <made up shape)
box is the hundredths spot</p>
<p>x = p/t, p is any one digit number, t is any two digit number</p>
<p>what is one possible value of x?</p>
<p>no jsmith7651, i think that was the range question. The barrel q just said he needs to equate both barrels.</p>
<p>(a, b+1) . . .</p>
<p>(a,b+1) was the choice I think</p>
<p>I think for that problem.. that has two answers...</p>
<p>it might be like.... even single integer/odd double integers or other way around!</p>
<p>inthemoney.. explain that problem for me!</p>
<p>Watch, you are right that 5 would work too but it was not an anawer choice only 2 would have worked from the choices that they gave</p>
<p>what did you guys get for the romal numeral one that was at the end of the section? only I and II?</p>
<p>usta90, there were two with roman numerals, could you say which one?</p>
<p>Inthemoney whats your reasoning for it being 3?</p>
<p>i cant remember the exact problem so if someone could state it that would be great</p>
<p>the one with the absolute value bars . .</p>
<p>if ur talking about the one with the circle.. it said </p>
<p>I) a
II) b...</p>
<p>i put E.. cuz both 1 and 2 work...and there was not i and ii so it had to be all 3..</p>
<p>i omitted about 6, everything else right, im so dumb i should've just guessed, better chance of going up....cr i probably got a 300 it was so damn hard for me.</p>
<p>I don't remember the answer choices well for the (a, b + 1) one, can anyone explain the full problem?</p>
<p>no not the circle one . . . by the way your answer for that was right, it was all three. i'm talking about the other one.</p>
<p>ok, i didnt take the test and my friend asked me how to solve it - 0,2,5,6 are the only ones that worked but from the choices that the posters presented 5 was on it - so i assumed that it was a choice. If indeed 2 was the only one of these that were available then yes, that is definitely the correct answer.</p>
<p>jsmith, that one was 3 only, i'm pretty sure
absolute value bars was just 1</p>
<p>no it was all the choices.</p>
<p>oh great! that seems so dumb.. i omitted that barrels one.. and then now if i get this wrong.. i'll be mad</p>
<p>For the circle problem, you have three locations where point (a,b) could be. </p>
<p>If it's on the x axis, then the distance between the center of the circle (at the origin) is a. </p>
<p>If it's on the y axis, then the distance between the center of the circle and the origin is b. </p>
<p>If it's at some other point on the circle, you have to apply the distance formula, so: </p>
<p>sqrt((a-0)^2 + (b-0)^2), or sqrt(a^2 + b^2) </p>
<p>So it's all three.</p>