<p>In the figure below, l || m and each circle is tangent to the other two circles at the labeled points. If each circle has diamter 8 and is tangent to one of the two lines, what is the distance, h, between l and m?</p>
<p>(A) 8 root 3
(B) (4 root 3) + 8
(C) (2 root 3) + 12
(D) 16
(E) (8 root 3) + 8</p>
<p>Please explain,</p>
<p>ok bro let my give u a hint that these three circles form an equilateral triangle, simply because they are tangent to each other…and i think u will know how to solve it. The answer is B, clam ur-self down and think what possible shapes it might form. Hope this helps</p>
<p>The answer is B.</p>
<p>Monte Cristo? darn i hate that film since it takes me 5 hours to finish watching it</p>
<p>I don’t like the film, only the book. Since it is more than 1200 pages, the book takes more than 5 hours to finish. But, at least for me, it was time well spent.</p>
<p>perhaps books r better</p>
<p>Hey Jwisgod,</p>
<p>Yeah, I saw that. But, I can’t seem to figure out how to find the altitude of the equilateral.</p>
<p>The length of the base is 4, the hypotenuse is 8. How do I find the third side???</p>
<p>Thanks for the help btw.</p>
<p>ok recon, since u know that the hyp is 8 the base is 4 then the height will be discovered by using Pythagoras Theorm which ----square root((8^2)-(4^2))= square root(48) or
(4 root 3). Now you will then have to add up the 2 remaing radius which it gives u an 8 in total. Hence the final answer will be square root(48)+8 or (4 root 3)+8 so answer (B)…solved </p>
<p>Hope this helps</p>
<p>regards</p>
