Discussion of 2009 AP BC Calc Free-Responce Answers

<p>bump this up please</p>

<p>Hey, if you make an attempt and somehow get the right answer (through guessing), do graders have to give you that point?</p>

<p>And if you do poorly on all three-four parts of the question, you have to get at least one point right? They can’t give you a 0 right…?</p>

<p>That being said, if I get around a 15 for FRQ, to get a 3 all I would need is a solid 20-25 MCQ score?</p>

<p>hmm…i think i ended up getting 50-52/54 on the free response…hopefully i’ll be good for a 5</p>

<p>databox…all you need now is about 10-14 points on the multiple choice, so based upon your free response score, i think that you can get those points…if you really did get a 52, then you are guaranteed to get a 4 and with just a mediocre mc score you will get a 5</p>

<p>I think I got 40-45 so all I need is like 3 points and I got my goal of a 4.</p>

<p>Ha, I think I got like 45/54 (1-2 blank, assuming 4 wrong) on the MC. I wanted a 5, but I messed up so badly on that on those FRQs, I think I’ll have to settle for a four, but we’ll see. I think 50% on those FRQs is realistic, so 5 is possibly. Yay.</p>

<p>if you got a 50% on the frq you should be more than golden to get a 5</p>

<p>Xav, your MC score is great, but 50% in FRQ? You probably underestimated yourself haha. I mean, there were 3 AB questions, which are jokes… i’m sure you’ll get a 5 :)</p>

<p>hey once you get your score report in july are you allowed to cancel a score, even if you pay?</p>

<p>I think I got around a 50% on FRQ because of a ton of stupid little mistakes…:(</p>

<p>Hopefully my MC is good enough to carry my score and I can pull off somewhere in the 70s.</p>

<p>Ren, you misunderstand me. I have a way to mess problems up. It’s a curse. I can do multivariable calculus, but I can’t count little squares. I got 1.8 for the square. ■■■. xD.</p>

<p>For the diver, I messed up the arclength and the angle question. The rock concert question is a blur to me, so I don’t know if I destroyed it or not. I messed up the euler’s method question somehow, but I solved the “hard” part which was the differential question. I think I got the whole table one correctly but I dont know and for the series, I messed up 6a) by expanding it (I dun even know why I did it XD. I hope they just give me the credit for the unexpanded series that I showed in my work prior to messing it up) and for some reason,I thought the 2nd derivative of (x - 1)^2 would be (x - 1) and thus I put x = 1 as the point of inflection. </p>

<p>I just messed up a part of every FRQ. Rather shameful. At least the MC was a joke. Complete and utter joke. I had time to go back and check my answers. There were only a handful that had me a little confused, but I discussed most of them with other people who did good and my arguments seemed to trump them so who knows. I hope for the best. ^^</p>

<p>Prism…they can give 0s on the M/C, but generally…if you write anything you get at least a few points (ie. integral signs…etc)</p>

<p>there was a different answer for 6b) i believe on another thread, does anyone know the definite answers to 6a) and 6b)</p>

<p>6a) just plug in (x-1)^2 for every time there is x in the given maclaurin series</p>

<p>6b) find the series by subracting 1 and then dividing by (x-1)^2 - there is an (n+1)! now because every series starts with n = 0 and the 2nd term is (x-1)^2/2! however the 2nd term is when n = 1 and 1! is not 2 so thats why</p>

<p>ok, this is what i did, but there seems to be some rumblings about whether you had to re-center the series. i think the above way is correct.</p>

<p>Stimulus, you also subtracted your terms by 1 right? Because its a taylor series centered at 1. And did you simply it? Because I didn’t simplify and it was very complicated looking and took up a lot of room. Just thought maybe I did something wrong</p>

<p>now i am even more confused, </p>

<p>what is your general term.</p>

<p>is it (x-1)^(2n)/(n+1)! or (x-2)^(2n)/(n+1)! or something completely different. i think i did not re-center my terms so i may have gotten that part wrong.</p>

<p>It’s x-1. Don’t worry about it. </p>

<p>I actually did it by hand because I was paranoid. xD</p>

<p>k thanks, that is good news at this point in time.</p>

<p>For part A? I think I got ((x-1)^(2n)/n!) - 1? Cause centered at x = 1</p>