Does anyone have a solution?

College Confidential Community
1

<p>You have a regular bottle filled with water. What is the fastest way to pour all the water out? You can't break the bottle or anything. What is the fastest way and why?</p>

<p>My solution was to position the bottle in such a way that water is coming out of the bottle exactly half of the cross-sectional area of the hole. Air would be coming into the bottle at the same rate as the water is leaving. The air would replace the missing water inside.</p>

<p>But there is a even FASTER way to do it. What is it?</p>

2

<p>ummm, just dump it?</p>

<p>haha i dont know, I really don't understand the question.</p>

<p>Maybe because I am not taking physics</p>

3

<p>Close it and throw it into a vacuum. The bottle would explode. No bottle = all the water is out of the bottle.</p>

4

<p>christalena2 - The question is basically: What is the FASTEST way to POUR water out of a bottle?</p>

<p>Venkat89 - I think you missed the part where I said, "You can't break the bottle or anything."</p>

<p>By the way, you can only POUR the water out. I need the angle or the position of the bottle.</p>

5

<p>You put the bottle into a dark, empty room for three hours.</p>

6

<p>^That does nothing. </p>

<p>What about heating up an oven to the highest temperature before the bottle starts to melt? Depending on how hot you can make it, the water should evaporate out really quickly and the bottle (hopefully) will remain intact.</p>

<p>If you must pour it, your idea is best, but maybe you would want the air pressure outside to be higher than inside the bottle .</p>

7

<p>Drink it realllllllllllllly fast.</p>

8

<p>hire someone fat to jump on it</p>

<p>funny visions</p>

<p>that POURS it out, right?</p>

<p>OHHHH.. ok.. this is against the rules..
but one of those collapse-able water bottles..? and then just ..push...//have the fat guy push? what?</p>

9

<p>I don't know...position it vertically?</p>

10

<p>volume of water leaving must be equal or less then the volume of air entering, or else a vacuum will be created which will hinder the gravitional force acting on the water. the idea is to let the water flow outvand make sure that air is entering, so the water shudnt be allowed to occupy the whole cross-sectional opening part</p>

11

<p>have a stronger vacuum to suck out all the water, which will cancel out the force of the vacuum inside the bottle</p>

12

<p>Is there actually a unique solution to this?</p>

13

<p>I don't know. I want to find out.</p>

14

<p>I like the fat guy jumping on it suggestion. It made me laugh.</p>

15

<p>hold the bottle in front of you horizontally</p>

<p>then turn it into a vertical position as fast as you can</p>

16

<p>Well, you could place it in a vacuum and open it while upside down. The air pressure at the back would blast the water out.</p>

<p>If you just pour it, you would need to adjust the angle in relation to how much water is left, in order to avoid the vacuum situation mentioned above.</p>

17

<p>this is your opening



[\         /]
  |       |
  |       |
  |       |
  |       |
  |       |
  |       |

tilt the bottle at such an angle that if you look parallel to the bottle, the water flows like this



[\         /]
  |      /|
  |     /~|
  |    /~~|
  |   /~~~|
  |  /~~~~|
  | /~~~~~|
  | ~~~~~~|

</p>

<p>you want to leave as little space in the cross sectional opening as possible so as to give as large an area for _____ volume of water to flow out while still avoiding a vacuum. as long as there exists at least some free space between the flow of water and the outer perimeter of the opening, air can come in. i'm sure there's some way to explain this with bernoulli's equation but i'm lazy as hell.</p>

<p>and yes, i know my diagram is upside down. oops.</p>

18

<p>Is the shaded area water? When I first looked at your diagram, thats what I thought. But when I finished reading your explanation, the empty space seemed like water.</p>

19

<p>Or you could just throttle the bottle very violently..</p>