Does MIT require CSS profile in order to give financial aid to international students?
If you are not willing to do the seconds of research that it takes to answer that question , I question whether you belong at MIT. There are going to be many many more difficult questions and procedures you are going to have to get exactly right to get accepted to an American college and get financial aid. You better start doing the research. You also have to double and triple check the answers, requirements and procedures because things change in an instant in any of these things.
Asking this question on a forum board is foolish because you MUST get the most current info for applying for these things. Not an off the cuff answer that anyone who Anders might know from last year , last week , Friday, that can be different for the fall. Please get your rear in gear and start doing the essential research yourself.
I don’t know why @cptofthehouse was so aggressive but yes you need to fill out the international student css profile
@Ronitsingh1405 , yes, most of the private colleges require CSS profile for Fin Aid. Also, FA for international students is limited.
For college specific questions, you should check their website and email them for any follow up questions.
I was aggressive because it would have taken him less time to google MIT international student FAFSA than post this question for anyone who feels like answering to this whether it’s current info or not.
If this student wants to have the best chance (which is miniscule as it is) of getting accepted with financial aid to any US college , it is essential that he does in depth current, to the moment research on each school and procedure. Any questions he asks should not be on a simple required procedure but more general opinion, and feel type things that cannot be gotten just from the web sites and procedural information. This is critical to any chance that s/he is successful. It’s key and I cannot emphasize this enough.
MODERATOR’S NOTE:
The original poster has asked a question for which there is a definitive answer. Since that answer has been provided, I am closing the thread.