domain TI 89 Math IIC

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1

<p>How do you find domain/range on the 89. Is there a way?</p>

2

<p>oh i got another question. How do you solve for "x" for log (sub 5) (x-3) = log (sub 25) (x-1). It would be log5(x-3)=log25(x-1)</p>

3

<h2>log(x-3)</h2>

<h1>log5</h1>

<h2>log(x-1)</h2>

<p>log25</p>

<p>Now, RHS also equals-</p>

<h2>log(x-1)</h2>

<p>log5^2
Which equals-</p>

<h2>log(x-1)</h2>

<p>2.log5</p>

<p>Cancel log5 on both sides ...</p>