<p>At the point of 750, I believe it is careless mistakes that might get you away from an 800.</p>
<p>However, some said that this book helped them STOP any careless mistakes they had/bridge the gap.</p>
<p>@IceQube: Can you give me a link for this SAT Math Bible you speak of?</p>
<p>^Yes, I can provide a link to Nova’s SAT Math Bible. </p>
<p><a href=“http://www.amazon.com/SAT-Math-Bible-Jeff-Kolby/dp/1889057487/ref=sr_1_2?ie=UTF8&qid=1312307901&sr=8-2[/url]”>http://www.amazon.com/SAT-Math-Bible-Jeff-Kolby/dp/1889057487/ref=sr_1_2?ie=UTF8&qid=1312307901&sr=8-2</a></p>
<p>@nothingto,</p>
<p>I just recieved my book today! lets see how it goes. 
If i have questions, do you mind if I ask you occasionally, since you are ahead of me?</p>
<p>^can you post updates as to how you like it please?</p>
<p>yeah sure, but I wont be starting to look at it until tomorrow</p>
<p>@Katrina0</p>
<p>Yes, PM me anytime you need a question, I’ll always be here :)</p>
<p>Hey guys I have been through about 20 of the 50 tips and took just the first section of the 1st practice test. I think its very different from other types of math books in that it focuses on more of the abstract problems. I really don’t think its too hard, but yes, some of the explanations do confuse me and I do not understand some of the solutions ( i will be asking cc people questions shortly ) . I think its worth a buy.</p>
<p>I took a test yesterday and got a 740 in math. Will Dr.Chungs get me a 800?</p>
<p>Let me just revive this thread.</p>
<p>Will Dr. Chung help me go from a 750 to a 800?</p>
<p>I have a question regarding Tip 13 practice problem 6.</p>
<p>If a fair die is thrown three times, what is the probability that a 5 comes up exactly two times?</p>
<p>The solution says: (1/6 x 1/6 x 5/6) x 3 = 5/72</p>
<p>I’m not understanding why it is multiplied by 3.
Isn’t it just 1/6 x 1/6 x 5/6?</p>
<p>thanks</p>
<p>@yujin623, the reason it is multiplied by 3 is because there are 3 different ways to get a 5 two times. You could have 5 5 another # , 5 another # 5 , or another # 5 5. So those 3 options are plausible so you need to multiply getting 2 5s in one way by 3. Get what I mean?</p>
<p>Yes I perfectly get what you mean. Thank you!</p>
<p>Could someone help clarify this problem for me?
XY + YX = 88</p>
<p>In the addition problem above, X and Y are distinct positive integers. How many different integer values of X are possible? (Answer = 7)</p>
<p>I thought X and Y were being multiplied so I got 2xy = 88 or xy = 44 and found all the factors of 44, but my answer was wrong. This sounds like a really silly/easy question, but I don’t really understand what I’m doing wrong…Thanks!</p>
<p>EDIT: Never mind, it seems like I had the right answer, but the book made a typo.</p>