<p>in the xy plane two points A (-2,-5) and B (3,2) are each reflected about the line y=x. What is slope of line containing points to which A and B are reflected?</p>
<p>Choices:
-7/5, -5/7, 1/7, 5/7, 7/5</p>
<p>Reflected across y=x, so the new points are: (-5,-2) and (2,3)</p>
<p>Slope formula says:</p>
<p>y2-y1/ x2-x1… So plugging in:</p>
<p>3-(-2)/ 2-(-5)</p>
<p>= 5/7</p>
<p>At face value, it seems a lot harder than it really is. Think about it one step at a time. First, you have to find the new points. Second, you have to substitute in for slope formula. Third, you have to make sure you do your algebra correctly.</p>
<p>This is an easy question, lol.</p>
<p>why is that when u reflect the pts, u switch the coordinates of the pts?</p>
<p>Asianandproud, relax. We’re not all rocket scientists like you.</p>
<p>Firelion, Good question. You’re reflecting across the line y=x. So if you were to graph that, it’d look like a diagonal line. If you have a graphing calculator, try graphing it. Remember, you’re REFLECTING each point across that line. </p>
<p>Yeah, sorry if that wasn’t the best of explanations. Maybe someone will be able to explain it better.</p>
<p>This is not a hard question and it has nothing to do wirh rocket science, no SAT math question is hard in fact they just seem overwhelming but there’s always a simple way to solve it that your mssing.</p>
<p>The slope of AB is (2 - (-5))/(3 - (-2)) = 7/5. When you reflect about the line y = x, the slope reciprocates (you see why?), so the slope of the new line is 5/7.</p>
<p>reciprocate means also switching the neg/pos signs so, why dont the signs switch?</p>
<p>Reciprocate just means “1 over something.” So if you reciprocate a/b, you get b/a.</p>