<h2>Go wild.</h2>
<p>Does anyone know the answer to the one with the two squares and a shaded region?</p>
<p>there was a cube with a triangle in it, it gave you the angle as 32 degrees and the line across from it as 20, i said 20/sin^-1(32) cus i thot the hypotenuse was it, but idk</p>
<ol>
<li>char…</li>
</ol>
<p>That’s what I put.</p>
<p>I put that one, too</p>
<p>your right with the cube</p>
<p>k so ther was a circle that looked like a unit circle, but i dont think it was, it said in traingle x^2+y^2=8^2 and it gave u like the point of (4,y) and u had to find area, i had no idea</p>
<p>well, the hypotenuse was the radius, so the hypotenuse was 8, and you solve for the missing side using the pythagorean theorem, and then you find the area using A=1/2bh</p>
<p>@sp3344
It’s a basic geometry question if you are familiar with the equation of a circle (x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center of the circle and r is the radius. Now this circle was around the origin so we didn’t need to worry about the center and since the equation has r^2, r would be 8 in this case. Now they also gave you the point (4,y) and that point connecting to the origin gave you the hypotenuse of a right triangle and the radius of the circle. Finally, the point (4,y) indicates 4 units to the right of the origin and y units up. So essentially, the short leg of the triangle was 4 units long, the hypotenuse was 8 units long, and you had to find the other leg of the triangle. With Pythagorean’s Theorem, you can find that length to be the sqr root of 48 or simplified, 4 x sqr root of 3. Now we can go ahead and find the area by doing 1/2bh. So we multiply 4 x (4 x sqr root of 3) and we get 16 x sqr root of 3. This answer divided by 2 or multiplied by 1/2 would equal 8 x sqr root of 3 which is the answer to the problem.</p>
<p>The y value was square root of 48. Then you just use formula for area of a right triangle, (1/2)bh. So you get (1/2)(4)(square root of 48, which is 4 on the the square root of 3)</p>
<p>The answer was 8 on the square root of three.</p>
<p>yeah, the area of the triangle on the plane was 8 root 3.</p>
<p>the area of the shaded region between two squares is 4 bc perpendicular lines at the center always divide a square into four parts of equal area.</p>
<p>what was the answer to the one where you had to find the ratio of the radius, and the triangle was inscribed in the circle?</p>
<p>2:1 10char</p>
<p>Oh my lord I think I gave the hypotenuse as the answer…ooops, not the area.</p>
<p>Okay so apparently the circle/traingle/circle one is 2:1 but how? Is there some formula or do you just have to think about it?</p>
<p>Can someone make a consolidated list?</p>
<p>1) 2 Squares with sides of 4 and 5, Find area. Ans: 4
2) Ratio 2:1
3) Median problem 3
4)</p>
<p>The one where you had to find the tax if the person made more than 200,000 a year… was it .1x-5100?</p>
<p>Yes it was</p>
<p>i forgot about the math problems… how did one solve the .1x-5100? I may have put it, but I forgot. what were other choices?</p>
<p>just look at the graph and see which works</p>