<p>A few math questions I thought were challenging:</p>
<p>The first one was something that said the terminal side of Quadrant II... and that the 0 (its a symbol that i dont know how to make on my computer) was sin 3/4.... what was the answer and how did you get it?</p>
<p>There was also y^8=4 and y^7= x/3..... i know the answer is 4x/3... but how did you get it?</p>
<p>and also the question about the garden problem where you needed to make 3 rows and each plant needed to be 2 feet from center adn 2 feeet from edge.</p>
<p>and the last one was that matrix question...</p>
<p>(y^8)=(y^7)(y)
4=(x/3)(y)
y=4x/3 tricksie, a little.</p>
<p>The quadrant one I wasn't positive about, but I got -4/sqrt(7). Using the pythagorean theorem you get sqrt(7) as the one side. And then opposite/adjacent = 4/root7, but it was a diff quadrant so negative.</p>
<p>I got 3/5 for the tangent one. i was thinking triangle (3,4,5), 5 the terminal angle, 3 the height and 4 the width. lol so I'm not very confident with that answer at all, I just wanted it to be easier than it was.</p>
<p>Is the tangent one the same one that had 4/(sqrt7) ? If it was i'm pretty sure that wasn't the answer because it wasnt a 3-4-5 triangle. SIN was 3/4, so the hypoteneuse itself was 4.</p>
<p>I'm pretty confident that it's 27, I mapped it out and everything. 16 doesn't even divide evenly by 3 and your answer should have since it was 3 rows in a rectangle</p>
<p>I hope it's 27 because that's what i guessed ;D That was C right ? (or H)? I guessed either 16 or 27.. but in the end i picked 27 i think, lol. one of the very very few i couldn't figure out</p>
<p>does anyone remember what the letter answer to the logarithms question was? i saw it and immediately skipped it just based on first glance. i went back and ruled out some but i'm not sure if i got it right</p>
<p>It was like log(1+A) - log(1-A) = log (something) - log (something)
The answer I think was (1+A)/(1-A) = (something)/(something)
cus when you subtract same base logs it's like dividing the values I think, not 100% on that one.</p>
<p>they didn't have to be two feet from the walkway, the CENTER of the rosebush had to be two feet from the walkway. and the centers of each of the rosebushes had to be two feet from each other. i think the wording is what made it so hard</p>