FRQ for AP Chem. 2009 Debate

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41

<p>Hydrogen bonding is too vague, if you know what it is, you should know that it’s simply a stronger form of Dipole dipole.</p>

<p>Looking good, I knew I missed the hybridization one as soon as I saw it, because I blanked on how to determine… (facepalm) I guessed P orbital, </p>

<p>H2S has 2 bonds, so it is sp. Am I right? (I assume it is, read thread) [too late, oh well]</p>

<p>Reactions were easier than I thought. REALLY EASY. I was expecting some random things (cough Barrons prep) but it was nice. [Paramagnetic? What. We didn’t learn a thing on that.]</p>

42

<p>what i said was that H2O has stronger dipole because it has hydrogen bonding, which is a very strong form of dipole, and H2S doesn’t. That’s right, isn’t it?</p>

43

<p>for the magnetic question:
Sulfur has unpaired electrons so it is paramagnetic
all of S-2 electrons are paired, so it is diamagnetic</p>

<p>paramagnetics are attracted to magnets</p>

44

<p>Does anyone know for the electron removing one, if we put “It is harder to remove electrons from Argon because it has more protons” if we would get full credit? I misread the question and thought it was harder instead of easier…</p>

45

<p>If it asked which one was easier and you said which one was harder, I think they’d give you credit. There were only two options.</p>

46

<p>Barg… I didn’t get the gas collecting question at all. I don’t see how you turn mL of beakerness into grams of beakerness. I ended up making up parts i and ii, in order to continue the question (which was really easy after that, but I have 0 points worth of “correct solutions”). f it all.</p>

47

<p>

It gave you density (g/L).</p>

48

<p>I ran out of time on that question. So I put “pour water”. i hope i get a point for that.</p>

49

<p>Did you guys use rounded values for the percent error in the gas collecting one? I used my exact calculator values, got 40.2g for d, and 8.64% for e. Will that matter?</p>

50

<p>where is the discussion for question 1 of the Free Response?</p>

51

<p>I am wondering the same thing as verddil. If we have an answer that is withing like .1 or so of their answer, will we still get credit? I wasn’t sure whether or not to use our sig fig answers to calculate each successive step or use the REAL numbers.</p>

52

<p>Was my 4 a i right? I am pretty sure that is the equation. But my friend thinks it is 4Fe3+ + 3C -> 3C4+ +4Fe because “that is how they want to see redox reactions.” That makes sense, since in their sample question and answer for that section, the redox reaction between magnesium and silver is written in my friend’s form. But then how come for answer 4 b on the 2008 test (answer is here <a href=“College Board - SAT, AP, College Search and Admission Tools”>College Board - SAT, AP, College Search and Admission Tools), they don’t put it in that form? I think it is because the sample question does not SAY it is a redox reaction, but in 4 b (2008) and 4 a (2009), they say it is a redox reaction and thus don’t want to see the exact charges of ONLY iron and carbon.</p>

<p>What do you all think?</p>

53

<p>4a was 2Fe2O3 + 3C -> 4Fe + 3CO2 iirc no splitting as these are solids and CO2 is a gas</p>

54

<p>Weren’t only the p orbitals involved in bonding, as they were only partially filled?</p>

55

<p>if i put down sp3, would i still get credit??
dammit that one extra number, i thought they were asking about the hybrid orbital</p>

56

<p>i think you’ll get at least partial credit for sp3.</p>

<p>anybody remember the acid-base equilibrium question (the first one)?</p>

<p>and for Question 3, on the part right before where they ask you to calculate the wavelength, did they asked you to calculate the bond energy in joules for a chlorine bond? the first post had the answers in molecules, and i don’t remember the question asking for the number of molecules, i thought it was the bond energy.</p>

57

<p>

Uhm. Why not? Isn’t hydrogen bonding a type of dipole-dipole interaction?</p>

<p>“A hydrogen bond is the attractive force between one electronegative atom and a hydrogen covalently bonded to another electronegative atom. It results from a dipole-dipole force with a hydrogen atom bonded to nitrogen, oxygen or fluorine (thus the name “hydrogen bond”, which must not be confused with a covalent bond to hydrogen).”
(<a href=“http://en.wikipedia.org/wiki/Hydrogen_bond[/url]”>http://en.wikipedia.org/wiki/Hydrogen_bond&lt;/a&gt;)</p>

58

<p>hmm… I might have accidently used R = .0821 instead of .08261… I will just lose the point for molar mass, but I will get the point for calculation of percent error right?</p>

59

<p>

</p>

<p>I believe the AP curriculum differentiates between the two. Someone correct me if I’m wrong.</p>

<p>Dipole-dipole interactions result from differences in electronegativity, while hydrogen bonding results from the hydrogen atom’s unshielded nucleus after it loses an electron.</p>

60

<p>i knew it should have been 1/2 for Cl2
but im not sure if thats what i put because i was debating over it
i panic sometimes lol</p>