GoldenMonkey SAT's AP Calculus BC Help

<p>I need to find find d^2y/dx^2 (Second Derivative) of x^2+y^2=6</p>

<p>A.) -6/y^3</p>

<p>B.) (-x/y)^2</p>

<p>C.) -[(x^2/y)+y]/y^2</p>

<p>D.) Both A and C</p>

<p>E. None of the above</p>

<p>I need a step by step process. Thanks in advance!</p>

<p>C
Dy/dx=-x/y
D^2y/dx^2= -((y+x(dy/dx))/y^2)
Then you plug in dy/dx</p>

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