<p>I have two questions</p>
<ol>
<li><p>If a and b are integers such that a+b<1000 and a/b=.625, what is the greatest possible value of b.</p></li>
<li><p>How many positive integers less than 1000 are multiples of 5 and are equal to 3 times an even integer.</p></li>
</ol>
<p>bump, please!</p>
<p>17/ b must be an integer and < 1000/(0.625+1)
18/ all of the ab0 ( 0<ab<=99)</p>
<p>that didnt really answer my question?</p>
<p>bump, someone else explain?
thanks</p>
<p>it’s from OC #9 test. hahahhaha I found it!</p>
<p>a/b = .625 which is also 5/8. So the ratio of a to b is 5 to 8. The SMALLEST integers they could be are 5 and 8 which adds up to 13. They could also be any integer multiples of 5 and 8, but the total has to stay under 1000. So…100o divided by 13 is 76 and change. Round down to 76 to get the biggest multiplier that works. Then, the largest allowable b value is 8 times 76 = 608. (And the largest a value is 5 times 76 = 380. The total of 608 and 380 is 988 which is under the 1000 mark – but any higher and you would go over the top.)</p>
<p>Hope that made sense. It’s a hard problem.</p>