Gruber's Math Workbook Help

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1

<p>Does anyone have Gruber's Math Workbook that can help me understand the problem on page 268.</p>

<p>((1/2)(AB)h)/((1/2)(AB)h)=1/3</p>

<p>Why is the second AB not AD since its the base of the whole triangle? And where did the 1/3 come from?</p>

2

<p>By the way, I understand why it’s 1/3 because the lines trisect the whole triangle in three equal parts which mean the area of one part is a third of the whole, but I want to understand it the way they did it in case I encounter more complex problems.</p>

3

<p>The second… what?</p>

4

<p>I mean’t the bottom of the fraction.</p>

5

<p>Oh no you’re right; it should be AD.</p>

<p>Otherwise the answer would be 1. Which would be wrong.
x/x=1 </p>

<p>Grubers has tons of mistakes.</p>

6

<p>Thanks! I thought I was missing something, but apparently not. This would’ve saved me much more time if I knew that earlier.</p>

7

<p>Wait, I don’t think it was a mistake because he talks about how the AB cancels out. But, I just don’t understand where the equation came from. Anyone else have Gruber’s Math Workbook that can help?</p>