<p>Here you go, i someone is able to figure it out and explain it.</p>
<p>In the xy-coordinate plane, a line intersects the y-axis at point P. If the y-coordinate of point P is equal to the slope of the line, then the line must contain which of the following points ?</p>
<p>A. (-1, -1)
B. (-1, 0)
C. (-1, 1)
D. (-1/2 , 1/2)
E. (1, 0) </p>
<p>Thank you ....</p>
<p>B. if the y corrdinate of point P is equal to the slope of the line, it means that (0, m).
you can then set up the equation.
(m-y)/(0-x)=m, only B would work.</p>
<p>I think B is the answer. take the line to be some y=mx+c. Then let point P be some (a,b)
Now, since slope=y co-od(b) and c=the y intercept(b)… So the final equation will look like this…y=bx+b=>
y=b(1+x)…so whenever x=-1, y=0;
=>(-1,0)=>(B) IS your answer choice:)</p>
<p>oh…and a=0(the point is on Y axis)</p>
<p>Now it’s perfectly clear, not that hard actually i missed the P = P part … that’s what i get for thinking all questions are easy :P</p>
<p>^ I got B too… do u have an answer key or sth?</p>
<p>Let the equation of the line be y = mx + m. Plugging in (-1,0), we get 0 = 0, which is true regardless of our choice of m. The answer is B.</p>