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<p>No idea. The answer was E. I just thought it had to be the largest angle because it's the largest side.</p>
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<p>No idea. The answer was E. I just thought it had to be the largest angle because it's the largest side.</p>
<p>no the answer is B</p>
<p>Has to be B. Looking at the orientation of the line, slope must be negative, leaving us with just A and B. Since the x coordinate is greater than the y coordinate (and the line is symmetric about the origin), y’-y < x’-x. Thus slope must be less then one as well, leaving us with B.</p>
<p>Ugh, I wish that was the hardest question. The SATs would be much easier. I hate my 670 in Math…</p>
<p>The answer is B. First of all, the slope is negative, so that leaves you with -2 or -.5 </p>
<p>Since the absolute value of run will be greater than the absolute value of rise, it is -1/2.</p>
<p>did you guys pick points to solve that?</p>
<p>No need to pick points. </p>
<p>|p| > |r| and the slope of the line is (r-0)/(p-0) = r/p. Since the denominator is larger than the numerator, the slope will be a number less than 1. It’s already obvious from the graph that slope is negative, so we’re looking for a slope between -1 and 0. The only choice that falls in that range is B.</p>
<p>So B really has nothing to do with the problem, you can use the origin?</p>
<p>This is a pretty easy questions… I solved it the same way as tetrisfan did</p>
<p>“So B really has nothing to do with the problem, you can use the origin?”</p>
<p>you can find the slope of a line with any two points on the line. the origin is a point on the line. point B only exists to confuse you.</p>
<p>Alternatively, since it doesn’t say it’s not drawn to scale you can just eyeball it and realize that it must be between 0 and -1.</p>
<p>Uhh it’s not that hard compared to others IMO. You know the is has to go farther left or right than it does up or down which means the slope has to be less than -1 which in this case, -.5 is the only choice that fits</p>
<p>The reason why it’s hard is becuase the SAT tests how well you can look at small pictures. It took me a good time to notice that it actually crosses at 0,0. </p>
<p>Only -2 and -1\2 work, but -2 means that |p|< |r|, so only -1\2 works.</p>
<p>This is why I hate the SAT math compared to the ACT. Instead of testing your mathmatical knowledge, it tests how well you can notice small details. If that were an ACT question, it would have specifically said it crossed through the point (0,0).</p>
<p>guys Im sorry if i didnt specify. I wanted this thread to die. It was on the 2nd page and you guys kept bringing it back. Basically, I gave you guys the wrong link ergo the wrong problem and i couldnt edit it back. I made a new thread with the right link</p>
<p>I noticed after I posted. :D</p>
<p>This one is harder than the other though. :P</p>
<p>really? i thought it was easier. hmmm lemme take it look… i havent bothered to read the explanations and stuff… anyhow thanks for every1 for helping so generously. and shame on the people yelling at me that its really easy and fail to answer the question</p>