<p>so you basically have this:
18 * (18)^(1/2) = r * (t)^(1/2).
so i would solve it like this:
set r as 18 (outside the root) and t as 18 (inside the root)
so factoring 18 gives 2 * 3^2.
You have to satisfy the requirement given, which is r>t.
therefore, you have to take the 3^2 out of the square root.
so you get this
(2 * 3^2) * (2 * 3^2)^(1/2)
(2 * 3^2) * 3 * (2)^(1/2) which is 2 * 3^2 * 3 * sqrt(2)
so you have
54 = r and t=2.
multiply and you get 108.</p>
<p>showing math is sort of confusing, so tell me if i need to clarify.</p>