<p>In the xy-coordinate plane, the graph of y = -x^2 + 9
intersects line L at ( p, 5) and (t, 7). What is the
least possible value of the slope of L?</p>
<p>(A) 6
(B) 2
(C) -2
(D) -6
(E) -10</p>
<p>I honestly think there is something wrong with the question wording or something.</p>
<p>Do you think so? It’s from the CB online course I think.</p>
<p>yah cuz like the smallest slope i got was something like -3.43 or something… and I did it a gazillion times and none of the answer options worked.</p>
<p>sorry i don’t have my book in front of me, but I know I’ve seen this problem before, either from a BB or online test. Are you sure it wasn’t (t,8) ?</p>
<p>I see the mistake now… the points are (p,5) and (t,-7)… in which case the correct answer will be “D”</p>
<p>For (P,5) and (T,7)</p>
<p>y = -x^2 + 9</p>
<p>5 = -P^2 + 9
p^2 = 4
P = + or - 2</p>
<p>7 = -T^2 + 9
T^2 = 2
T= + or - root(2)</p>
<p>Slope is: (Y-Y1)/(X-X1)</p>
<p>In order to make it as large as possible, we’ll do</p>
<p>(7-5)/(2-root(2)) </p>
<p>I’m sure you wrote the question wrong but you can use my reasoning.</p>
<p>Thanks.
I got it too. Wasn’t that hard.</p>