<p>SAT</a> Math Problem</p>
<p>Can someone show me how to solve this problem?</p>
<p>A stystem of equations</p>
<p>^That’s not what I asked - I asked for someone to show me how …</p>
<p>Assume x is one.</p>
<p>Then you have 1+2/3+1/2, which equals 13/6, or answer A.</p>
<p>Just figure out what y and z equal in terms of x. In this case, y is 2x/3 and z is x/2</p>
<p>This problem cries out for substitution.</p>
<p>Assume x is 1, as the above poster said, and work your way from there.</p>
<p>Just do it one at a time. 2x=3y, divide both sides by 3 and you get 2/3x=y. Do the same with z, 2x=4z, and you should get 1/2x=z.</p>
<p>Now just add them up, x+2x/3(previously y)+1x/2(previously z)= 13x/6.</p>
<p>Since no one else has said it…you could also just make up the easiest numbers you can find that fit:</p>
<p>2x = 3y = 4z…let’s make them all come out to 12. So x = 6, y = 4 and z = 3.</p>
<p>Based on those numbers, x + y + z = 6 + 4 + 3 = 13. And now the question reads: 13 is how many times 6? So it’s 13/6.</p>