<p>I read on here that Com. College courses are usually easier than AP courses. My school doesn't offer any APs, so I decided to dual-enroll so that I'd be prepared for college by taking a college course and getting a credit. </p>
<p>I was just wondering, if CC courses are easier than APs, are AP courses what a college level course is like, or are the CC courses more like a college course. Are APs just harder to get you ready for the demands and study habits needed in college?</p>
<p>It really depends on the community college and on the course. I spent 2 years at a cc before transferring to a State U to finish a BSCE. During the transfer orientation for engineers, the State U counselor said “Where ever you have been, it will be harder here.” (they think pretty highly of themselves). But it wasn’t harder, really. It was just more of the same. Those of us from the same CC did fine. We had used the same texts and done the same problems as the students who had been at State U all 4 years. We were just as prepared as they were. </p>
<p>That said, some CC’s have more watered down coursework, because many of the students are coming from REALLY bad backgrounds and are not prepared to do more. They have to have some remedial work to get them back on a good track.</p>
<p>It may be possible to find out how your cc is by asking around.</p>
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This is definitely true. My son got AP 5s for Chem, Calc BC, and Physics C (both) by taking CC classes and doing no AP-specific studying other than making sure he had covered all the topics (he had).</p>
<p>Also, what do you mean by “harder”? The AP class is likely to have more homework, which takes more time, but may or may not go more deeply into the material.</p>
<p>Regardless of which is harder or better, the CC class is probably more like a university course because it has less homework and more expectation that you will take care of yourself. </p>
<p>I’d recommend taking AP tests after CC courses because many schools will be more likely to give credit for APs than for transfer classes.</p>