Help on 2 Math Problems

<p><a href="http://i.imgur.com/Wayi6fZ.png%5B/url%5D"&gt;http://i.imgur.com/Wayi6fZ.png&lt;/a> </p>

<p>I was able to solve the first question but it took me quite a while and was wondering what the most effective method is. Then for the second problem I got 9 and I got it wrong. It was 18. I can't understand how it could be different than 9, something I'm missing probably.</p>

<p>A = # of $2 cards sold
B = # of $3 cards sold
C = # of $5 cards sold
A = 2B
B = 2C
$2(A) + $3(B) + $5(C) = $57
All that is given from the question itself
Since we want to know what B is, we make A and C equal to B proportionately.
So the new equation is:
$2(2B) + $3(B) + $5(0.5B) = $57
$9.5B = $57
B = 6 cards sold. </p>

<p>I think this would be a level 4 problem so don’t worry if it takes you a bit longer to do it. </p>

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<p>You should always draw out such things I think </p>

<p>Hope this helps!</p>

<p>Ah thanks so much. Yeah 37 was a really dumb mistake… for some reason I used 3 as the base instead of 6.</p>