help on probability/data management

Test Preparation
1

From a class of 14 boys and 9 girls, how many ways can I choose a committee of 6 to analyze classroom productivity with and equal number of boys and girls?
a) 30,576
b)252,252
c)48
d)126

Thanks in advance and could you give me an explanation to how you got the answer

2

Choose 3 boys and 3 girls.

ways = (14C3)(9C3) = 36484 = 30576

3

thanks @MITer94

4

What does C3 represent?

5

@IneffableMind I’m using nCk to denote the “choose” operation, i.e. nCk = n!/((n-k)!k!) (maybe I should just use “14 choose 3”).

Alternatively I could use $\binom{14}{3}$ but I’d think only a few on this forum would understand.