<p>Math Question:</p>
<p>h(x)=14 + x^2/4.
If h(2m)=9m, what's a possible value of m?</p>
<p>I tried to factor, didn't work.</p>
<p>Please help.</p>
<p>h(x) = 14 + x^2/4.</p>
<p>so if h(2m) = 9m, plug in 2m for x</p>
<p>you get h(2m) = 14 + (2m)^2/4 = 9m</p>
<p>then:</p>
<p>14 + 4m^2/4 = 9m</p>
<p>14 + m^2 = 9m</p>
<p>move 9m to the other side.</p>
<p>m^2 - 9m + 14 = 0</p>
<p>factor:</p>
<p>(m-7)(m-2) = 0 </p>
<p>(i found the factors by considering two numbers that add up to -9 and multiply to 14. but if you have trouble doing this step in your head, get a quadratic formula program for your calculator that can do it for you. it's legal on the test, so why waste time trying to figure it out for yourself?)</p>
<p>thus: m = 2 or m=7.</p>
<p>did i get it right?</p>
<p>plug in 2m for x, set it equal to 9m...and solve for m?</p>
<p>lol, looks like we posted @ same time..yes to the above.</p>
<p>hannah's right! i factored wrong.. opps</p>